Easy Puzzle #5 - One Possible Solution Approach…
	NB:  There is only one final solution to this Sudoku puzzle…
	A	B	C	D	E	F	G	H	I
1
2	AA			BB			CC				Reference to 3x3 Blocks AA, BB & CC
3
4
5	DD			EE			FF				Reference to 3x3 Blocks DD, EE & FF
6
7
8	GG			HH			II				Reference to 3x3 Blocks GG, HH & II
9
	A	B	C	D	E	F	G	H	I
1			9			8	7		5		Easy Puzzle #5 - October 5, 2005
2		1			5			9	6		Original puzzle as published on joe-ks.com…
3		4	5			7	2		8
4		5	4		1	3	6
5			6		8	4			3
6	3				7		5		4
7	4		7			5		3	1
8		8	2	9	3	1		6	7
9		9			4	6
	A	B	C	D	E	F	G	H	I
1			9			8	7		5		Step 1: #5 is in Rows 4 & 6: #5 MUST go in Cell D5…
2		1			5			9	6
3		4	5			7	2		8
4		5	4		1	3	6
5			6	5	8	4			3
6	3				7		5		4
7	4		7			5		3	1		Step 2: #7 is in Rows 7 & 8: #7 MUST go in Cell D9…
8		8	2	9	3	1		6	7
9		9		7	4	6
	A	B	C	D	E	F	G	H	I
1			9			8	7		5		Step 3: #8 is in Columns E & F: #8 MUST go in Cell D7…
2		1			5			9	6
3		4	5			7	2		8
4		5	4		1	3	6				Step 4: #5 is in Columns G & I: #5 MUST go in Cell H9…
5			6	5	8	4			3
6	3				7		5		4
7	4		7	8		5		3	1
8		8	2	9	3	1		6	7
9		9		7	4	6		5
	A	B	C	D	E	F	G	H	I
1			9			8	7		5		Step 5: #7 is in Rows 1 & #3: where does it go in
2	7	1			5			9	6		Block AA Row 2? Two choices: Cells A2 or C2,
3		4	5			7	2		8		BUT #7 is already in Column C (@ C7), so
4		5	4		1	3	6				#7 MUST go in Cell A2…
5			6	5	8	4			3
6	3				7		5		4
7	4		7	8	2	5		3	1		Step 6: Only one more # left in Block HH:
8		8	2	9	3	1		6	7		#2 MUST go in Cell #E7…
9		9		7	4	6		5
	A	B	C	D	E	F	G	H	I
1			9			8	7		5		Step 7: #8 is in Rows 1 & 3: #8 MUST go in Cell C2…
2	7	1	8		5			9	6
3		4	5			7	2		8
4		5	4		1	3	6				Step 8: #6 is in Rows 4 & 5: #6 MUST go in Cell D6…
5			6	5	8	4			3		Why? Because #6 is already in Column F…
6	3			6	7		5		4
7	4		7	8	2	5		3	1
8		8	2	9	3	1		6	7
9		9		7	4	6		5
	A	B	C	D	E	F	G	H	I
1			9			8	7		5		Step 9: Block EE needs only 2 more #s: #2 & #9:
2	7	1	8		5		3	9	6		Because #9 is already in Column D, Cell D4 can't contain
3		4	5			7	2		8		#9 - so Cell D4 MUST be #2…
4	8	5	4	2	1	3	6				… and then Cell F6 MUST be #9…
5			6	5	8	4			3
6	3			6	7	9	5		4		Step 10: #3 is in Columns H & I: #3 MUST go in Cell G2…
7	4		7	8	2	5		3	1
8		8	2	9	3	1		6	7		Step 11: #8 is in Columns B & C: #8 MUST go in Cell A4
9		9		7	4	6		5			because #8 is in Row 5 (@ E5)…
	A	B	C	D	E	F	G	H	I
1			9			8	7		5		Step 12: Row #4 needs 2 more #s: #7 & #9:
2	7	1	8		5		3	9	6		Cell H4 can't be #9 (See #9 in Column H @ H2), so
3		4	5			7	2		8		#7 MUST go in Cell H4…
4	8	5	4	2	1	3	6	7	9		and therefore #9 MUST go in Cell I4…
5			6	5	8	4			3
6	3			6	7	9	5		4
7	4		7	8	2	5		3	1		Step 13: #8 is in Rows 7 & 8: #8 MUST be in Cell G9
8		8	2	9	3	1		6	7		because #8 is already in Column I (@ I3)…
9		9		7	4	6	8	5
	A	B	C	D	E	F	G	H	I
1			9			8	7		5		Step 14: #8 is in Rows 4 & 5: #8 MUST go in Cell H6…
2	7	1	8		5		3	9	6
3		4	5			7	2		8		Step 15: Where does #2 go in Block II?
4	8	5	4	2	1	3	6	7	9		Because #2 is already in Column G, there's only 1 cell
5			6	5	8	4			3		for #2 to go in Block II: at Cell I9…
6	3			6	7	9	5	8	4
7	4		7	8	2	5		3	1
8		8	2	9	3	1		6	7
9		9		7	4	6	8	5	2
	A	B	C	D	E	F	G	H	I
1			9			8	7		5		Step 16: Complete Block II: need 2 #s: #4 & #9…
2	7	1	8		5		3	9	6		#4 can't go in Cell G7 because it's already in Row 7 (A7)
3		4	5		9	7	2		8		so #4 MUST go in Cell G8… and #9 MUST go in G7…
4	8	5	4	2	1	3	6	7	9
5			6	5	8	4			3		Step 17: #9 is in Rows 1 & 2 and MUST go in Cell E3
6	3			6	7	9	5	8	4		(because #9 is already in Column D @ D8)
7	4		7	8	2	5	9	3	1
8		8	2	9	3	1	4	6	7
9		9		7	4	6	8	5	2
	A	B	C	D	E	F	G	H	I
1			9		6	8	7		5		Step 18: Only one more # left in Column F: #2 MUST go in F2
2	7	1	8	4	5	2	3	9	6
3		4	5		9	7	2		8		Step 19: Only one more # left in Column E: #6 MUST go in E1
4	8	5	4	2	1	3	6	7	9
5			6	5	8	4			3		Step 20: Only one more # left in Row 2: #4 MUST go in D2
6	3			6	7	9